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衡水金卷先享题2022-2023学年度高三一轮复习周测月结提升卷(老高考)3英语考卷答案

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衡水金卷先享题2022-2023学年度高三一轮复习周测月结提升卷(老高考)3英语试卷答案,以下是该试卷的部分内容或者是答案亦或者啥也没有

衡水金卷先享题2022-2023学年度高三一轮复习周测月结提升卷(老高考)3英语

34.A推理判断题。根据最后一段内容可知人工智能创作的音乐很难和贝多芬创作的音乐区分开。利用两年的时间,这个团队完成了贝多芬的第十交响曲。可推断团队的努力没有白费。故选A。

衡水金卷先享题2022-2023学年度高三一轮复习周测月结提升卷(老高考)3英语

【12达|版权所有,未经许可禁止外传,一经发现追究法律责任】M:Well,wehavequiteafewchoiceshere:ostcardswithourlocalscenery,hand-madewoolenhatsandsomeotherthingsoverthere.W:Oh.Thosearequitenice.IllgetawoolenhatforMomandsomepostcardsforDad.ButwhatshouldIgetformysonandhusband?M:Howoldisyourson?W:He’sateenager.He’sinhighschoolnow.M:WhataboutaSwissarmyknifeforhimandahand-madeleatherbeltforyourhusband?W:Goodidea!Ipreferapairofbadmintonbatformyson.Howmuchforallofthese?M:Letmeadditup.Awoolenhat,20dollars;asetofpostcards,5dollars;apairofbadmintonbat,10dollars;andaleatherbeltfor23dollars.Alltogether,58dollars.W:Theselookverybeautiful!M:Bytheway,doyouneedsomethingforyourself?Howdoyoulikethissilkscarf?It’sonsaleattheTnoment.W:Oh?Howmuchisit?M:18dollarseach,butthirtyfortwOW:OK,whynot?IwilltaketvNO.Text10Helloeveryone.MynameisKaylaHartwell.TodayI’mgoingtotalkaboutyourfirefightertrainingprogram.Theprogramlastsforthreemonths.Duringthistime,you’lllearnaboutladdersafetyandsomeequipment.Thecollegehasovertwoacresofgrounds,wherewecancreaterealfiresforstudentstopractiseonn一undersafeconditions,ofcourse.Wewilllearnhowtofightfiresontrains,firesinbuildingsandfiresatpetrolstations.Thisisaveryimportantpartofthecoursebecauseithelpstogetusedtoworkinginveryhot,smokyplaces.Ifyouwanttoapplyforthiscourse,youmustbe18yearsofageorolder,haveafulldrivinglicenseandbeveryfit.Youmustalsobeabletoworkaspartofateamandbeabletosolveproblemsinverydifficultsituations.Theotherthingyouneedtorememberbeforeapplyingforthiscourseisthatyouwilloftenbeworkingwhenyourfriendsareenjoyingthemselves.Ifyouhaveanyquestions,pleasecomeandseemeinmyoffice,whichisRoom116nexttoRoom118onthefirstfloor.

3(1)ACE两分子间距由无穷远逐渐靠近,至到达n之前的过程中分子力不断做正功;不断改进,热机效率无法达到100%6;在外界干预下,可以从单一热源吸收热量全部转化为有用功;布朗运动是固体小颗粒的运动,而非固体分子的运动;温度为物体分子平均动能的标志正确选项为ACE(2)解:①撒去外力后左侧向下的压强时S=20×10B=2A(2分)右侧向下的压强十S=1.5×10B=15A(2分)故活塞均下降,且左侧降至水平管口设右侧降至高为x处,此时封闭气体压强变为p=1.5对封闭气体p(4AS+AS2)=1.5A(3h1+xS2),x=0.5h(3分)②活塞对气体做正功W>0气体温度不变内能不变根据热力学第一定律N=Q-W气体放热(3分)

衡水金卷先享题2022-2023学年度高三一轮复习周测月结提升卷(老高考)3英语

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