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2024届全国名校高三单元检测示范卷(二)数学.试卷答案

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exposingthhs6ynepeimene,TepgrniopansmdcramiAcstorteemiaefdaioofthetask,whichtook20minutes.英语试题（长郡版）第5页（共10页）

分析直接利用函数的奇偶性的定义判断即可．

解答解：（1）f（x）=5x+1；因为f（-x）=-5x+1≠f（x），f（-x）=-5x+1≠-f（x），
所以函数f（x）=5x+1既不是奇函数也表示偶函数．
（2）f（x）=-$\frac{2}{{x}^{2}}$+1．
f（-x）=$-\frac{2}{{（-x）}^{2}}+1$=-$\frac{2}{{x}^{2}}$+1=f（x），所以函数是偶函数．

点评本题考查函数的奇偶性的判断与应用，是基础题．

2024届全国名校高三单元检测示范卷(二)数学.