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[广东大联考]广东省2023-2024学年度高二年级上学期期中考试(10月)数学. 考卷答案

[广东大联考]广东省2023-2024学年度高二年级上学期期中考试(10月)数学.试卷答案,我们目前收集并整理关于[广东大联考]广东省2023-2024学年度高二年级上学期期中考试(10月)数学.得系列试题及其答案,更多试题答案请关注微信公众号:趣找答案/直接访问www.qzda.com(趣找答案)

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[广东大联考]广东省2023-2024学年度高二年级上学期期中考试(10月)数学.试卷答案

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高考复习(ZJZ)第22期综合能力评估试题(16)参考答案及部分解析参考答案1-5CCBAA6-10BABCA11-15BACBB16-20AABCC21-25CBDBA26-30DCBDA31-35BDCBA36-40DCGAF41-45DBCBA46-50DDAAB51-55CBACD56.than57.of58.trapping59.investigated60.isproduced61.successfully62.a63.toturn64.achievement65.effective写作第一节Onepossibleversion:DearChris,It'sgreattoreceiveyourlastemail.I'mfairlypleasedtolearnthatyouhavewonfirstprizeintheshortvideocontestforoverseasstudentsheldbyourcity.I'mwritingtooffermycongratulationstoyou.Itcameasnosurprisetomethatyouwonfirstprize,because,asIknow,youhaveatalentformakingshortvideosandhavemadeeveryefforttopracticemakingtheminyoursparetime.I'msogladthatyourconstanteffortfinallypaidoffandyourpersistencewasawarded.Congratulationsagainonyoursuccess!Yours,LiHua第二节Onepossibleversion:PootPootlikestositonAtlas'backwhensheliesonthefloortoreadduringhomeschoolingAndhealwayswaveshislittletailhearingAtlas'voice.WhateverAtlasdoes,hedoes:watchingTV,playing,orsleeping.HelovestoplaywithAtlasandthechickens,evenstandingontopofourdogswhentheylieonthefloor.Now,weighinginattenpounds,PootPoothashisownareaoutside.Hehasanewfriend,atwo-month-oldgoatnamedDotsy,whoisalreadythesamesizeashim.WheneverAtlasstepsfootoutsidethedoor,PootPootscreamsuntilshecomesovertogethim.AtlaspicksstrawberriesandbeansfromthegardenforPootPootandherself.Theonlythinghelovesmoreisdeliciouscheeseballs.Thepairoftenplayhide-and-seekinthetallgrass,AtlaswaitinguntilPootPootturnsaround,thenrunningawaytohide,PootPootcryingandjoggingashefollowsthesoundofhervoice.Thislittlekidhasalreadybroughtsomuchjoyintoourlivesandhasbecomeaspecialpartofourfamily部分解析阅读

分析由条件利用同角三角函数的基本关系、二倍角公式化简所给的式子,证明2sin2α•sin2β+2cos2α•cos2β-cos2α•cos2β=1即可.

解答解:∵cos2αcos2β=(cos2α-sin2α)(cos2β-sin2β)
=cos2αcos2β-cos2αsin2β-sin2αcos2β+sin2αsin2β,
∴2sin2α•sin2β+2cos2α•cos2β-cos2α•cos2β
=2sin2α•sin2β+2cos2α•cos2β-(cos2αcos2β-cos2αsin2β-sin2αcos2β+sin2αsin2β)
=cos2α•cos2β+sin2α•sin2β+cos2αsin2β+sin2αcos2β
=(cos2α•cos2β+cos2αsin2β)+(sin2α•sin2β+sin2αcos2β)
=cos2α+sin2α=1,
故得证.

点评本题主要考查同角三角函数的基本关系、二倍角公式的应用,属于中档题.

[广东大联考]广东省2023-2024学年度高二年级上学期期中考试(10月)数学.

关于作者: yun

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